Given, coordinate (x,y)=(2√2,−3√2) Let new coordinates be (x′,y′). Then, x′=x‌cos‌θ+y‌sin‌θ and y′=−x‌sin‌θ+y‌cos‌θ Here, θ=45° ∴x′=2√2‌cos‌45°+(−3√2)‌sin‌45° =2√2.
1
√2
−3√2.
1
√2
=2−3=−1 and y′=−2√2‌sin‌45°+(−3√2)‌cos‌45° =−2√2.