Given data PA0=70mmHg Ideal solution ⟶ obeys Raoult's law xB=0.2⇒xA=1−0.2=0.8 Total vapour pressure of solution P‌total ‌=84mmHg ‌ Temperature = ‌300K‌ (constant) ‌ We are asked to find PB0 (vapour pressure of pure liquid B ). Step 1: Apply Raoult's Law P‌total ‌=PA+PB=xAPA0+xBPB0 Substitute known values: 84=(0.8)(70)+(0.2)(PB0) Step 2: Simplify ‌84=56+0.2PB0 ‌84−56=0.2PB0 ‌28=0.2PB0 Step 3: Solve for PB0 PB0=‌