We are given these starting amounts:
[AO2]=1mol∕L[BO2]=1mol∕L[AO3]=1mol∕L[BO]=1mol∕LKc=16We need to find the equilibrium concentration of
AO3.
Step 1: Write the reaction equation.
AO2(g)+BO2(g)⇌AO3(g)+BO(g)Step 2: Set up an ICE (Initial, Change, Equilibrium) table.
At the start (initial):
[AO2]=1,[BO2]=1,[AO3]=1,[BO]=1Let
x be the amount that reacts.
Change in concentrations: beginarrayccccAO2BO2AO3BO\−x−x+x+xAt equilibrium:
[AO2]=1−x[BO2]=1−x[AO3]=1+x[BO]=1+xStep 3: Write the equilibrium expression and solve for
x.
Kc===16Take the square root of both sides:
=4Solve for
x :
1+x=4(1−x)1+x=4−4x1+x+4x=41+5x=4 5x=3x=0.6Step 4: Find the equilibrium concentration of
AO3.
[AO3]=1+x=1+0.6=1.6mol∕L
