‌z=x+iy ‌‌‌2|z−2−3i|=3|z+i−2| ‌‌‌‌ Let ‌z=x+iy ‌‌‌2|(x−2)+i(y−3)| ‌‌‌=3|(x−2)+i(y+1)| Squaring on both sides, we get ‌‌‌‌‌‌4x2−16x+16+4y2−24y+36 ‌=9x2−36x+36+9y2+18y+9 ⇒5x2+5y2−20x+42y−7=0 ‌‌ Centre ‌≡(2,‌