We are given: current I=4mA=4×10−3A and flux φ=32×10−6Tm2. Step 1: Find the inductance ( L ). The relationship between flux, inductance, and current is φ=LI. So, L=‌
φ
I
=‌
32×10−6
4×10−3
=8×10−3H. Step 2: Find the energy stored in the inductor. The formula for energy stored is E=‌
1
2
LI2. Plug in the values: E=‌
1
2
×8×10−3×(4×10−3)2. Calculate the value: E=64×10−9J.
