In acidic condition, KMnO4(Mn=+7 oxidation state ) reduced by H2O2 to Mn2+ So, x=Mn2+ In basic condition KMnO4(Mn=+7 oxidation state ) is reduced by H2O2 to MnO2y=MnO2 Acidic 2KMnO4+5H2O2+3H2SO4→2MnSO4+K2SO4+8H2O+5O2 Basic 2KMnO4+3H2O⟶2MnO2+2KOH+2H2O+3O2