Given, curve, y=x3 ∵ Slope of tangent to the curve at any point (x1,y1) on the curve is =
dy
dx
|(x1,n1) So,
dy
dx
=3x2 ∴ Slope of tangent at (x1,y1) is mT=3x12 ∵ Tangent is parallel to X-axis ⇒mT= Slope of X-axis ⇒mT=0 ⇒3x12=0 ⇒x1=0 ⇒y1=0 ∴ Point of contact is (0,0)