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AP EAPCET 24-Aug-2021 Shift 2 Paper
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Section:
Physics
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© examsnet.com
Question : 90
Total: 160
The distance between the carbon atom and the oxygen atom in a carbon monoxide molecule is
1.1
Å
. Given, mass of carbon atom is 12 a.m.u and mass of oxygen atom is 16 a.m.u. Calculate the position of the centre of mass of the carbon monoxide molecule.
6.3
Å
from the Carbon atom
1.0
Å
from the Oxygen atom
0.63
Å
from the Carbon atom
0.12
Å
from the Oxygen atom
Validate
Solution:
Given that, mass of oxygen,
m
0
=
16
amu
Mass of carbon,
m
c
=
12
amu
Distance between them,
r
=
11
Å
Let
x
be the distance of centre of mass from carbon atom
By using expression of centre of mass for two particle system,
X
com
=
m
1
x
t
+
m
2
x
2
m
1
+
m
2
Assuming centre of mass at orgin, we get
X
COM
=
0
=
m
C
(
−
x
)
+
m
O
(
r
−
x
)
m
c
+
m
O
m
c
x
=
m
o
(
r
−
x
)
m
c
x
+
m
0
x
=
m
0
r
x
=
m
o
m
c
+
m
o
r
By substituting the values, we get
x
=
16
16
+
12
×
(
1.1
)
Å
=
0.63
Å
Hence, position of centre of mass is
0.63
Å
from carbon atom.
© examsnet.com
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