=2.5N Similarly normality of acidB N‌acid ‌B=0.625N Volume of acid A needed for 1 L of 1 N solution ‌N‌acid ‌A×VA‌ final ‌=N‌final ‌×V‌final ‌ ‌VA‌ final ‌=‌
1×1
2.5
=0.4L‌‌‌⋅⋅⋅⋅⋅⋅⋅(i) Volume of acid B needed for 1 L of 1 N solution, VB‌ final ‌=‌