Given, parabola is y2=x and t1=2t2=−4 and t3=6. So, intersection of tangents at t1 and t2, then tangents are 2y=x+1 and −4y=x+4 Solving these two equations, we get y=(‌
−1
2
) and x=−2 So, point L=(−2,−‌
1
2
) Now, intersection of tangents at t2=−4 and t3=6, then tangents are −4y=x+4,6y=x+9 Solving these two, we get x=−6,y=‌
1
2
So, print M=(−6,‌
1
2
) Now, intersection of tangents at t1=2 and t3=6, so tangents are 2y=x+1 and 6y=x+9 Solving these two equation, we get x=3,y=2 So, point N=(3,2) Area of triangle with vertices L(−2,−‌
