Let m= mass of steam condensed. Then, m grams of steam forms m grams of water at 100∘C which further losses heat and comes at 90∘C. Final mixture is water at 90∘C Now using Heat lost = Heat gained, we gel Heat lost by steam in condensation + Heat lost by water formed at 100∘C = Heat gained by water at 24∘C ‌⇒mL+mc(100−90)=100(c)(90−24) ‌⇒m(540+1×10)=100×1×66 ‌⇒m=‌
