Test Index

BITSAT 2013 Solved Question Paper

© examsnet.com

Question : 2

Total: 150

A man runs at a speed of 4 m/s to overtake a standing bus. When he is 6 m behind the door at t = 0, the bus moves forward and continuous with a constant acceleration of 1.2 m/s2. The man reaches the door in time t. Then,

4 t = 6 + 0.6 t2
1.2 t2 = 4 t
4 t2 = 1.2 t
6 + 4 t = 0.2 t2

Go to Question:

Prev Question

Next Question