U = {x : x5–6x4+11x3–6x2 = 0} Solving for values of x, we get U = {0, 1, 2, 3} A = {x : x2 – 5x + 6 = 0} Solving for values of x, we get A = {2, 3} and B = {x : x2 – 3x + 2 = 0} Solving for values of x, we get B = {2, 1} A ∩ B = {2} ∴ (A ∩ B)' = U – (A ∩ B) = {0, 1, 2, 3} – {2} = {0, 1, 3}