Solution:
We first write the elements of the set R. i.e. R={(1,4),(4,1),(2,3),(3,2)}
Since, (1,1)∉R⇒R is not reflexive.
Now as, (1,4)∈R⇒(4,1)∈R and (2,3)∈R
⇒(3,2)∈R
So, R is symmetric
Now, (1,4)∈R and (4,1)∈R
⇒(1,1)∈R
Thus, R is not transitive.
Hence, R is symmetric but neither reflexive nor transitive.
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