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BITSAT 2017 Solved Question Paper
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© examsnet.com
Question : 19
Total: 150
A particle of mass m moving in the x direction with speed 2v is hit by another particle of mass 2m moving in the y direction with speed v. If the collision is perfectly inelastic, the percentage loss in the energy during the collision is close to
56%
62%
44%
50%
Validate
Solution:
Initial momentum of the system
p
i
=
m
×
2
√
ˆ
i
+
2
m
×
ˆ
v
ˆ
j
=
√
(
m
×
2
v
)
2
+
(
2
m
×
v
)
2
(magnitude)
=
2
√
2
m
v
=
2
√
2
m
Final momentum of the system =3mV
By the law of conservation of momentum
2
√
2
m
v
=
3
m
V
⇒
2
√
2
v
3
=
V
combined
Loss in energy
∆
E
=
1
2
m
1
V
1
2
+
1
2
m
2
V
2
2
−
1
2
(
m
1
+
m
2
)
V
c
o
m
b
i
n
e
d
2
∆
E
=
3
m
v
2
−
4
3
m
v
2
=
5
3
m
v
2
=
55.55
%
© examsnet.com
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