Given, the freezing point of pour water =273K The freezing point of the solution =272.4K Depression in the freezing point ∆Tf=273−272.4 Kf=1.86Kg∕mol ∆Tb=Kb×m Molality (m)=
∆Tf
Kf
=
0.6
1.86
=0.322m ∆Tb=0.512×0.322 =0.164K Boiling point of the solution =373+0.164=373.164K