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BITSAT 2022 Solved Question Paper
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© examsnet.com
Question : 25
Total: 130
One mole of an ideal diatomic gas undergoes a process as shown in the figure. The molar specific heat of the gas in the process is
3
R
2
R
2
5
R
2
7
R
2
Validate
Solution:
👈: Video Solution
In the curve,
V
∝
1
T
⇒
V
=
m
1
T
where,
m
=
slope of curve.
⇒
V
T
=
constant
∴
T
d
V
+
V
d
T
=
0
.
.
.
.
.
.
.
.
.
.
(
i
)
⇒
d
V
=
−
V
T
d
T
As,
Q
=
Δ
U
+
W
C
d
T
=
C
V
d
T
+
p
d
V
.
.
.
.
.
.
.
(
i
i
)
C
d
T
=
C
V
d
T
−
p
T
V
d
T
⇒
C
=
C
V
−
p
V
T
=
C
V
−
R
(
∵
p
V
T
=
R
)
For diatomic gas,
C
V
=
5
2
R
∴
C
=
C
V
−
R
=
5
2
R
−
R
=
3
R
2
© examsnet.com
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