In a cyclic process, the change in internal energy
(∆U) is zero. According to the first law of thermodynamics:
∆U=∆q+∆WSince
∆U=0, it follows that:
∆q=−∆WFrom the graph, the work done (
∆W ) is equal to the area under the curve. In this case, the process involves a circular path, so the work done can be calculated as the area of the circle:
Area of circle
=Ï€r2Given that the radius
(r) of the circle is half the difference between the maximum and minimum values on the graph,
r=‌=10Thus, the area is:
π×(10)2=π×100Therefore, the heat absorbed
(∆q) is:
∆q=100πJ