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Test Index
BPSC 64th Prelims Exam 16 Dec 2018 Solved Paper
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© examsnet.com
Question : 130 of 150
Marks:
+1
,
-0
If
S
=
10
∑
n
=
1
(
2
n
+
1
2
)
,
then
S
is
55
1
2
56
111
115
1101
2
Validate
Solution:
S
=
10
∑
n
=
1
(
2
n
+
1
2
)
Then
S
=
10
∑
n
=
1
2
n
+
10
∑
n
=
1
1
2
=
2
10
∑
n
=
1
n
+
10
×
1
2
=
2
(
10
)
(
10
+
1
)
2
+
5
[
Note:
1
+
2
+
3
.
.
.
n
=
n
(
n
+
1
)
2
]
=
110
+
5
=
115
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