x = L.C.M. of (7, 8, 9) - 3 = 504 - 3 = 501 x3+2x2+x−3=(x−1)(x+1)(x+2)−1 = 500 × 502 × 503 - 1 Remainder when 500 × 502 x 503 -1 is divided by: 11 = 4 3=0 4=3 Required remainder = least possible number which when divided by 11,3 and 4 leaves remainder 4,0 and 3 respectively Such least no. is 15.