P=15100(1×2×3×....×100)=15100×100! Highest power of 2 in P = 97 (2 will be deciding factor for number of zeroes because number of fives will be greater than number of zeroes in this number) Q=2520+50(1×2×3x..×50)=52000×50! Highest power of 2 in Q = 47 So Highest power of 2 in
P2
Q
×101767=2×97+1767−47=1914 Hence, number of zeroes = 1914.