{x} = x - [x] or {x} + [x] = x The given equation 5[x] + 3{x} = 6 + x ⇒ 2[x] + 3([x] + {x}) = 6 + x reduces to 2[x] + 3x = 6 + x or 2[x] + 2x = 6 or [x] + x = 3 Since 3 and [x] are both integers, in the above equation x must also be an integer. ⇒ [x] = x Hence, 2x = 3 or x =
3
2
This contradicts what we assumed above. So no real value of x satisfies the given equation.