Let the cost of one chair =₹x Cost of one table =₹y According to question, 10x+6y=6200 ...(i) and 3x+2y=1900 ...(ii) ⇒ 9x+6y=5700 ...(iii) On subtracting equation (iii) from equation (i), we get 10x+6y=6200 ⇒ −9x+6y=5700 ⇒ x=500 ∴ x=₹500 From equation (i), 5000+6y=6200 ⇒ 6y=1200 ⇒ y=₹200 ∴ Cost of 4 chairs and 5 tables =4x+5y =4×500+5×200 =2000+1000=₹3000