Given, Molarity of CuSO4 solution (c)=1M, i.e. 1mol∕L ∵1mol of Cu2+ ions require 2F of charge for complete deposition by electrolysis. ∴ On passing 2F charge, all Cu2+ ions deposited and no Cu2+ left in CuSO4 solution. So, the molarity of CuSO4 solution will be zero.