Test Index

CGPET 2018 Solved Paper

Section: Physics

Question : 2 of 150

Marks: +1, -0

P

Q

Solution:

According to given figure, three

1\ \text{µF}

capacitors are connected in series combination. So, their resultant capacitance,

\frac{1}{C_1}=\frac{1}{1}+\frac{1}{1}+\frac{1}{1}=3

C_1=\frac{1}{3}\ \text{µF}

Now, capacitor

C_1

is connected in parallel combination with

1\ \text{µF}

capacitor. Hence, equivalent capacitance between the

P

and

Q

C_{PQ}=C_1+1=\frac{1}{3}+1=\frac{4}{3}\ \text{µF}

Go to Question:

Prev Question

Next Question