So, voltage across 50Ω and 30Ω resistor, V1=I1×50=0.1×50=5V V2=I1×30=0.1×30=3V ∵ Three branches are connected in parallel combination, therefore voltage across each branch will be equal. ∴V1+V2=V3 ⇒ 5+3=V3 ⇒ V3=8V Applying KCL at point B, I2=I1+I3=0.1+