Formula of butane diol is
C4H10O2.
∴ It's molecular mass
=(4×12)+(10×1)+(2×16)=90 Given, mass of butane diol
(w)=0.9g ∴n===0.01mol where,
n= number of moles
At STP,
n= ∴V=n×22.4L or
V=n×22400(mL) or
V=0.01×22400 or
V=224mL ∴(1) is the correct statement.
2. When 2 -iodobutane reacts with NaI, it gives alkyl di-iodide in which iodine atoms are attached with the
2° -carbon. Thus, due to steric-hindrance it will undergo
SN1 reaction. Hence, we get racemic mixture.
∴ Statement
(2) is correct.
3. Structure of 2 -methyl butane is as follows:
H3−H−H2−H3 ∵ It has two similar groups, present on
C2 carbon atom. It is not optically active.
∴ Statement
(3) is wrong.
4.
C4H8 does not show 7 -isomers, as it has only four carbon atoms.
∴ Statement
(4) is wrong.
∴ Option (c) is the correct option.