Given, the perimeter of a triangle = 12 cm i.e., a + b + c = 12 cm we know that in any triangle, sum of any two sides is always greater than third side ∵ a + b + c = 12 ∴ 3 + 4 + 5 = a + b + c ∴ a = 3, b = 4, c = 5 3 + 4 > 5 ⇒ a + b > c 4 + 5 > 3 ⇒ b + c > a and 3 + 5 > 4 ⇒ a + c > b Hence, there are 3 posible triangles.