Given, the area of a quadrilateral =227.2cm2 Let, d1 = first diagonal = 7.2 cm + 8.8 cm = 16 cm and d2 = second diagonal According to question, Perpendiculars from the opposite vertices to a diagonal i.e., quadrilateral is a rhombus Therefore, Area of a rhombas =
1
2
×d1×d2 ⇒227.2cm2=
1
2
×16×d2 d2=
227.2
8
= 28.4 cm Hence, the length of the diagonal = 28.4 cm.