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CTET 2 Math and Science Jan 2015 Paper(HM)
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© examsnet.com
Question : 54
Total: 150
4
x
2
+
y
2
+
14
x
−
7
y
−
4
x
y
+
12
के गुणनखण्डों में एक गुणनखंड है
2
x
+
y
+
4
2
x
−
y
−
3
2
x
+
y
−
4
2
x
−
y
+
3
Validate
Solution:
4
x
2
+
y
2
+
14
x
−
7
y
−
4
x
y
+
12
=
4
x
2
+
y
2
+
12
x
+
2
x
−
6
y
−
y
+
9
+
3
−
4
x
y
=
[
(
2
x
2
)
+
(
−
y
)
2
+
(
3
)
2
−
4
x
y
−
6
y
+
12
x
]
+
2
x
−
y
+
3
=
(
2
x
−
y
+
3
)
2
+
(
2
x
−
y
+
3
)
=
(
2
x
−
y
+
3
)
(
2
x
−
y
+
3
+
1
)
=
(
2
x
−
y
+
3
)
(
2
x
−
y
+
4
)
अतः दिए गये व्यंजक के गुणनखंडों में एक गुणनखण्ड
(
2
x
−
y
+
3
)
है।
© examsnet.com
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