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CTET 2 Math and Science Sep 2014 Paper
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© examsnet.com
Question : 49
Total: 120
If one angle of a triangle is 130°, then the angle between the bisectors of the other two angles is
65°
115°
130°
155°
Validate
Solution:
We know that
∠
A
+
∠
B
+
∠
C
=
180
∘
130
∘
+
∠
B
+
∠
C
=
180
∘
∠
B
+
∠
C
=
180
∘
−
130
∘
=
50
∘
Dividing both sides by 2
∠
C
+
∠
B
2
=
50
2
=
25
Now ΔBOC
∠
C
2
+
∠
B
2
+
∠
B
O
C
=
180
∘
∴
∠
C
=
180
∘
−
(
∠
B
+
∠
C
2
)
=
180
∘
−
25
∘
=
155
∘
© examsnet.com
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