Let r be the radius of the circle. Since, the perimeter of the circle is 6π then,2πr=6π r=3 Then, the area of the circle is=πr2=π(3)2=9π Since, the area of the triangle and the area of the circle are equal. Then,
1
2
×base×height=9π
1
2
×8×height=9π 4×height=9π height =
9
4
π height =2.25π Hence, the required height of the triangle is 2.25π.