CTET Class I to V 8 Feb 2026 Shift 2 Paper

Concept:A number is divisible by 36 only if it is divisible by both 4 and 9. The divisibility rules are: for 4, the last two digits must be divisible by 4; for 9, the sum of all digits must be divisible by 9.Explanation:Step 1: Check divisibility by 4. The last two digits of the given number 72$x$292 are 92. Since $92 \div 4 = 23$, a whole number, the condition for 4 is satisfied for any value of $x$.Step 2: Now check divisibility by 9. Sum of all digits = $7 + 2 + x + 2 + 9 + 2 = 22 + x$. For the number to be divisible by 9, $22 + x$ must be a multiple of 9. The smallest multiple of 9 greater than 22 is 27, so $22 + x = 27 \Rightarrow x = 5$. (Any other multiple, like 36, would give $x=14$, which is not a single digit, so $x=5$ is the only valid digit.)Step 3: Compute $(3x+2)$. Substituting $x=5$, we get $3 \times 5 + 2 = 15 + 2 = 17$.Answer:The value of $(3x+2)$ is 17, which corresponds to option C (17).