GIVEN: One of the diagonals of a rhombus is 18 cm and the area of the rhombus is 216 cm2 CONCEPT: Diagonals of a rhombus bisect each other and are perpendicular to each other FORMULA USED: Area of rhombus = 1/2 × d1 × d2 d1 and d2 are the diagonals of rhombus. CALCULATION: Using the formula: 216 = 1/2 × 18 × d2 ⇒ d2 = 24 cm Now we know that the diagonals of a rhombus bisect each other and are perpendicular to each other
So, in triangle AOB: AB2=AO2+BO2 ⇒ AB2=144+81 ⇒ AB2 = 225 ⇒ AB = 15 cm ∴ side of the rhombus = 15 cm∴ side of the rhombus = 15 cm