Let the equation of line which is perpendicular to 5x−2y=7, is 2x+5y=λ . . . (i) Given lines are 2x+3y=1 . . . (ii) and 3x+4y=6 . . . (iii) On solving Eqs. (ii) and (iii), we get x=14,y=−9 Since the Eq. (i) is passing through the point (14,−9) ⇒2(14)+5(−9)=λ ⇒28−45=λ ⇒λ=−17 ∴ Equation (i) becomes 2x+5y=−17 or 2x+5y+17=0