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EAMCET Engineering 2006 Solved Paper
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© examsnet.com
Question : 17
Total: 160
The temperature of a thin uniform circular disc, of one metre diameter is increased by
10
∘
C
. The percentage increase in moment of inertia of the disc about an axis passing through its centre and perpendicular to the circular face : (linear coefficient of expansion
=
11
×
10
−
6
∕
∘
C
)
0.0055
0.011
0.022
0.044
Validate
Solution:
Increase in area of disc
∆
A
=
A
(
2
α
)
∆
t
=
π
(
0.5
)
2
(
2
×
11
×
10
−
6
)
×
10
=
0.000055
π
New area of the disc,
A
′
=
A
+
∆
A
∴
A
′
=
π
(
0.5
)
2
+
0.000055
π
or
π
r
′
2
=
0.250055
π
m
2
or
r
′
=
0.500055
m
Increase in moment of inertia.
I
′
−
I
I
=
(
0.500055
)
2
−
(
0.5
)
2
(
0.5
)
2
=
0.00022
=
0.022
%
© examsnet.com
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