=c Let Young's modulus of steel is Y1 and of brass is Y2. ∴Y1=
F1⋅l1
A1⋅∆l1
. . . (i) and Y2=
F2⋅l2
A2∆l2
. . . (ii) Dividing Eq. (i) by Eq. (ii), we get
Y1
Y2
=
F1⋅l1
A1⋅∆l1
F2⋅l2
A2⋅∆l2
or
Y1
Y2
=
F1⋅A2⋅l1⋅∆l2
F2⋅A1⋅l2⋅∆l1
. . . (iii) Force on steel wire from free body diagram T=F1=(2g) newton Force on brass wire from free body diagram F2=T′=T+2g=(4g) newton Now, putting the value of F1,F2, in Eq. (iii), we get