GATE Civil Engineering (CE) 2018 Shift 1 Solved Paper

Direct bending tensile stress,
fa=150MPa
Direct shear stress, ‌‌q=50MPa
According to IS 800:2007, clause 10.5.10.1.1
The equivalent stress fe=√fa2+3q2≤‌

fu

√3γmw

Note : The above check for combination of stress need not be done for fillet welds where the sum of normal and shear stresses does not exceed fwd [Clause 10.5.10.1.2. (b)]
Thus, ‌‌fa+q=150+50=200MPa
fa+q>fwd(=184.75MPa)
⇒‌‌re=173.21MPa
Thus, the weld is designed for an equivalent stress of 173.21MPa.