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GATE Civil Engineering (CE) 2018 Shift 2 Solved Paper
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© examsnet.com
Question : 41
Total: 65
A car follows a slow moving truck (travelling at a speed of
10
m
/
s
) on a two-lane two-way highway. The car reduces its speed to
10
m
m
/
s
and follows the truck maintaining a distance of 16
m
from the truck. On finding a clear gap in the opposing traffic stream, the car accelerates at an average rate of
4
m
∕
s
2
, overtakes the truck and returns to its original lane. When it returns to its original lane, the distance between the car and the truck is
16
m
.
The total distance covered by the car during this period (from the time it leaves its lane and subsequently returns to its lane after overtaking) is
64
m
72
m
128
m
144
m
Validate
Solution:
Overtaking time,
T
=
√
4
s
a
=
√
4
×
16
4
=
4
s
e
S
=
Space heady way
=
16
m
a
=
Acceleration
=
4
m
/
s
2
Distance travelled by vehicle
=
S
2
S
2
=
u
T
+
1
2
a
T
2
=
10
×
4
+
1
2
×
4
×
4
2
=
72
m
© examsnet.com
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