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GATE Mechanical Engineering (ME) 2018 Shift 1 Solved Paper
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© examsnet.com
Question : 40
Total: 65
A solid block of 2.0 kg mass slides steadily at a velocity V along a vertical wall as shown in the figure below. A thin oil film of thickness h=0.15mm provides lubrication between the block and the wall. The surface area of the face of the block in contact with the oil film is
0.04
m
2
. The velocity distribution within the oil film gap is linear as shown in the figure. Take dynamic viscosity of oil as
7
×
10
−
3
P
a
-s and acceleration due to gravity as
10
m
/
s
2
Neglect weight of the oil. The terminal velocity
V
(
i
n
m
/
s
)
of the block is____________ (correct to one decimal place).
Your Answer:
Validate
Solution:
Terminal velocity is a constant velocity i.e. the net acceleration is zero.
So,
Σ
F
net
=
m
a
m
g
−
τ
A
=
0
τ
A
=
m
g
µ
V
h
A
=
m
g
7
×
10
−
3
×
V
0.15
×
10
−
3
×
0.04
=
2
×
10
V
=
10.714
m
/
s
© examsnet.com
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