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GATE Mechanical Engineering (ME) 2019 Shift 1 Solved Paper
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© examsnet.com
Question : 47
Total: 65
In orthogonal turning of a cylindrical tube of wall thickness
5
m
m
, the axial and the tangential cutting forces were measured as
1259
N
and
1601
N
, respectively. The measured chip thickness after machining was found to be
0.3
m
m
. The rake angle was
10
∘
and the axial feed was 100
m
m
∕
m
i
n
. the rotational speed of the spindle was
1000
r
p
m
. Assuming the material to be perfectly and Merchant's first solution, the shear strength of the material is closest to
722
M
P
a
200
M
P
a
920
M
P
a
875
M
P
a
Validate
Solution:
N
=
1000
r
p
m
, rake angle
(
α
)
=
10
∘
Feed (f)
=
100
m
m
/
m
i
n
=
100
/
1000
=
0.1
m
m
/
r
e
v
=
t
Chip thickness ratio (
r
)
=
wncut chip thickness
cut chip thickness
=
0.1
0.3
=
1
3
Shear strength is given by
τ
s
=
F
s
sin
ϕ
b
t
Where,
F
s
=
shear force
ϕ
=
Shear angle
b
=
width
h
=
5
m
m
Using
tan
ϕ
=
r
cos
α
1
−
r
sin
α
=
0.33
cos
10
1
−
0.33
sin
10
=
0.345
Or,
φ
=
19.02
F
s
=
F
c
cos
φ
−
F
t
sin
φ
=
1606
cos
19.02
−
1259
sin
19.02
=
1103.29
N
So,
τ
s
=
1103.29
sin
19.02
5
×
0.1
=
719.12
M
P
a
© examsnet.com
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