X<15 Given y≤10 But x≥y 10≤x≤15 Given above the feasible regions max. revenue will happen at (15,10)∴ max revenue = 14×2000+10×3000......(i) For Shweta
Let units of A=X1 Let units of B=Y2 Given X2≤10&X1<20&X1≥X2≥10 x2≤10&10≤x1<20 Maxima will occur at (19,10). Max revenue =19×2000+10×3000........ (ii) Difference =(ii)−(i)=5×2000=10000Rs.=10 Thousands