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GATE Mechanical Engineering (ME) 2020 Shift 2 Solved Paper
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© examsnet.com
Question : 60
Total: 65
Water flows through a tube of
3
c
m
internal diameter and length
20
m
. The outside surface of the tube is heated electrically so that it is subjected to uniform heat flux circumferentially and axially. The mean inlet and exit temperatures of the water are
10
∘
C
and
70
∘
C
, respectively. The mass flow rate of the water is
720
k
g
/
h
. Disregard the thermal resistance of the tube wall. The internal heat transfer coefficient is
1697
W
/
m
2
⋅
K
.
Take specific heat
C
p
of water as
4.179
k
J
/
k
g
⋅
K
.
The inner surface temperature at the exit section of the tube is
∘
C
(round off to one decimal place).
Your Answer:
Validate
Solution:
Dinner = 3 cm, L = 20 m
Net heat flux
=
Total heat gain by water
Total surface area
=
˙
m
C
p
(
T
0
−
T
i
)
π
D
i
L
=
720
×
4.179
×
10
3
×
60
3600
×
π
×
0.03
×
20
=
26604.340
W
m
2
Heat flux at the exist
=
26604.34
w
m
2
q
′
′
=
h
[
T
exit
−
T
0
]
26604.34
=
1697
×
(
T
exit
−
70
)
The inner surface temperature at the exist section of the tube in
=
26604.34
1697
+
70
=
85.67
°
C
© examsnet.com
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