Since triangle ABC is inscribed in a semicircle, it must be a right triangle. The area of the triangle is thus
1
2
10 × 24 = 120. Using the Pythagorean Theorem, the diameter of the circle = AC = 26. The area of the circle is thus (π)r2 = (π)132 = (π)169. The area of the semicircle is thus
169π
2
= 84.5π. The area of the shaded region = area of the semicircle − area of the triangle. This can be expressed as 84.5π − 120.