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Haryana Police Constable Model Paper 1
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© examsnet.com
Question : 24
Total: 100
The value of
tan
70
°
tan
20
°
+
sin
2
80
°
+
sin
2
10
°
is
0
1
2
√
3
2
Validate
Solution:
Given
:
tan
2
70
°
tan
2
20
°
+
sin
2
80
°
+
sin
2
10
°
Concept
used
:
we
know
that
,
tan
(
π
2
−
θ
)
=
cot
θ
also,
sin
(
π
2
−
θ
)
=
cos
θ
Formula
used
:
cot
θ
tan
θ
=
1
cos
2
θ
+
sin
2
θ
=
1
Calculation
:
tan
70
°
tan
20
°
+
sin
2
80
°
+
sin
2
10
°
⇒
tan
(
π
2
−
20
°
)
tan
20
°
+
sin
2
(
π
2
−
10
°
)
+
sin
2
10
°
⇒
cot
20
°
tan
20
°
+
(
cos
2
10
°
+
sin
2
10
°
)
⇒
1
+
1
⇒
2
∴
The
value
is
2
.
© examsnet.com
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