We have to calculate AD with D being the final position and A being the initial position. We know that AB = 10 m, BC = 6 m and CD = 2 m. ED=BC=6m . BE=CD=2m . AE=AB–BE=(10−2)m=8m . Using Pythagoras right angled theorem, AD2=AE2+ED2 AD2=82+62=64+36=100m . AD=√100=10m . Hence, the distance between his final and initial position is 10m.