Haryana Police Constable Model Paper 6

Given:
A pump can fill a pot in 2 hours.
With leakage, the pot can be filled in 2

1

3

hours
Concept:
If a tap can fill a tank in x hours, then the tank filled by the tap in 1‌hour=

1

x

of the total tank.
Calculation:
Work done in 1 hour by the pump =

1

2

Work done in 1 hour by leakage and pump =

3

7

Work done by the leakage in 1 hour =(

1

2

)–(

3

7

)
⇒

(7–6)

14

=

1

14

∴ The leakage can empty the pot in 14 hours.