Given - −4−1+2+5+………. Formula used - for an arithmetic progression, nth term formula Tn=a+(n−1)×d where, a = first term, n = number of term, d = common difference Solution - Let the 10th term be T10. −4−1+2+5+………. ⇒a=−4,n=10,d=(−1+4)=3 ⇒T10=−4+(10−1)×3 ⇒T10=23 ∴ 10th term of progression = 23.