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IBPS Clerk Mains 2018 Paper
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© examsnet.com
Question : 94
Total: 190
If 6 years are subtracted from the present age of Panas and takes 25% of that then we get the present age of his only son. 4 years ago, his daughter’s age is 7 years more than his son. Sum of daughter’s present age and his wife’s present age is 10 years more than Panas’s present age, then find the present age of Panas if average of present age of entire family is 30.25 year?
45 year
50 year
60 year
40 year
36 year
Validate
Solution:
(b) Let the present age of Panas be x yr.
Present age of his son =
x
−
6
4
yr
Present age of his daughter =
[
x
−
6
4
+
7
]
yr
Present age of his wife
= (x + 10) –{
[
x
−
6
4
+
7
]
}
=
3
x
+
18
4
yr
ATQ
x
+
x
−
6
4
+
[
x
−
6
4
+
7
]
+
3
x
+
18
4
=
121
x = 50 yr
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