Let, original speed of car = 100 a km/hr So, increased speed of car = 100a × 1.2 = 120 a km/hr ATQ, 3600 / 100a−
3600
120a
=
50
60
36
a
−
30
a
=
5
6
6
a
=
5
6
5a = 36 a = 7.2 Original speed of car = 7.2×100 = 720 km/hr Increased speed of car = 720×1.2=864 Car travel with its increased speed in 3 hrs. =864×3km.=2592 km